Thursday, 2 May 2019

JPSC Recruitment 2019 | Professor Jobs | लोक सेवा आयोग भर्ती

JPSC Recruitment 2019 Vacancy details: झारखंड लोक सेवा आयोग में 262 पदों पर ‘असिस्टेंट प्रोफेसर’ की भर्ती Recently JPSC Notification released and invites Sarkari Naukri Jobs application. Check Qualification & eligibility conditions, how to apply & other rules are given below Download Notification, Exam Dates Check All Details at Free Job Alert.


JPSC Recruitment 2019: झारखंड लोक सेवा आयोग में 262 पदों पर ‘असिस्टेंट प्रोफेसर’ की भर्ती

झारखंड लोक सेवा आयोग
पद का नाम: असिस्टेंट प्रोफेसर
Jharkhand Public Service Commission
Name Of Post: Assistant Professor
No. of Vacancies: 262
Advertisement No.: 03/2019
Starting Date: 23.04.2019
Last Date: 15.05.2019


Exam Eligibility: Age Limit, Qualification & Fee Details

Qualification: Post Graduation in relevant discipline.
Age Limit: Maximum 30 Years. As on 01.08.2019. Age relaxation is as per Jharkhand Govt. norms.
Application FeeFor GEN/OBC/EWS Candidates : Rs.600/-
For SC/ST Candidates : Rs.150/- through offline mode by challan form at SBI Bank or Online mode.

Useful Link for Download Notification PDF, Apply Online Application Form, Exam Date & Procedure

Download Notificationhttp://www.jpsc.gov.in/data/Advertisement_no_03_2019.pdf 
Apply Online Nowhttps://bit.ly/2Lf0SSl 
Organization Websitewww.jpsc.gov.in 
JPSC Recruitment 2019


Important Link for JPSC Exams

Download Notification File PDF  
Online Form Application 
Admit Card Download
Answer Key Download
Result
Joining Letter

 Top 10 Government Jobs India 2019




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